/* not included yet */
/*
 * trail - traveller support library
 * Copyright (c) 2004 Danny Milosavljevic
 *
 * This program is free software; you can redistribute it and/or modify
 * it under the terms of the GNU Lesser General Public License Version 2.1,
 * or (at your option) any later version.
 *
 *
 * This program is distributed in the hope that it will be useful, but 
 * WITHOUT ANY WARRANTY; without even the implied warranty of
 * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU Lesser
 * General Public License for more details.
 *
 * You should have received a copy of the GNU Lesser General Public License
 * along with this program; if not, write to the Free Software Foundation,
 * Inc., 59 Temple Place - Suite 330, Boston, MA 02111-1307, USA.
 */
#include <gtk/gtk.h>

/*

Calculations by Nathalie Kopaczewski :)

dannym: I have a rectangle "M" which is for the total available space
dannym: then I have a smaller rectangle "I" which is centered in "M"
dannym: (in it there will be a cute icon but thats beside the point ;))

dannym: and now there is space between the rectangle M and the rectangle I
in that space I want to place additional cute icons, err emblems (rectangle E0, E1, E2....),
so that it will be aligned in a circle.

dannym: they will orbit the main icon like planets orbit the sun :)
dannym: just the sun is rectangly :)

dannym: corner conditions are thus 
	I < M
	C between I and M, C not intersecting
	center(E0) somewhere on C
	center(E1) somewhere on C
	...
	
	E.x not intersecting with M and not intersecting with I
	E.x as big as possible (but not bigger :))
            
dannym: searched for is:
	- ideal radius for C so that E.x as big as possible
	- E.x

Nat: length(I) < lenght(M)/sqrt(2)
            14:49
            Nat: if =, then length(E.x)= 0. And if >, then it's impossible

Nat: if you set the size of the main icon, I can give you formulas for the radius of C and size of E;x

Nat: I name LE, LI, LM the length of the side of the squares E;x, I and M
Nat: RC the radius of C
Nat: and S2 is square root of 2

RC=(LM+LI)/(2+S2)
LE=(LM-S2*LI)/(1+S2)

Nat: and here, you see in the formula giving LE that you must have what I told you before: LM-S2*LI must be >=O
Nat: if =0, LE=0 though :P

RC=(LM-LE)/2
LI=(LM-(1+S2)*LE)/S2

Nat: actually, the LE I am calculating with these formulas is the max
dannym: I see :)
Nat: max so that it stays inside M and outisde I.
Nat: but you can use the same RC and a smaller LE, it will just not touch I and M when rotating
            
*/

/*
gdouble	s2 = sqrt(2)
*/